4h(3h+2)=h=12

Solution for 4h(3h+2)=h=12 equation:

4h(3h+2)=h=12

We move all terms to the left:

4h(3h+2)-(h)=0

We add all the numbers together, and all the variables

-1h+4h(3h+2)=0

We multiply parentheses

12h^2-1h+8h=0

We add all the numbers together, and all the variables

12h^2+7h=0

a = 12; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·12·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*12}=\frac{-14}{24}
=-7/12
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*12}=\frac{0}{24}
=0
$