(-10z+28)+(-4z+40)=2(-2z+29)

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Solution for (-10z+28)+(-4z+40)=2(-2z+29) equation: 



(-10z+28)+(-4z+40)=2(-2z+29)

We move all terms to the left:

(-10z+28)+(-4z+40)-(2(-2z+29))=0

We get rid of parentheses

-10z-4z-(2(-2z+29))+28+40=0



We calculate terms in parentheses: -(2(-2z+29)), so:

2(-2z+29)

We multiply parentheses

-4z+58

Back to the equation:

-(-4z+58)



We add all the numbers together, and all the variables

-14z-(-4z+58)+68=0

We get rid of parentheses

-14z+4z-58+68=0

We add all the numbers together, and all the variables

-10z+10=0

We move all terms containing z to the left, all other terms to the right

-10z=-10

z=-10/-10

z=1

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