(-10z+28)+(-2z+29)=(-4z+40)

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Solution for (-10z+28)+(-2z+29)=(-4z+40) equation: 



(-10z+28)+(-2z+29)=(-4z+40)

We move all terms to the left:

(-10z+28)+(-2z+29)-((-4z+40))=0

We get rid of parentheses

-10z-2z-((-4z+40))+28+29=0



We calculate terms in parentheses: -((-4z+40)), so:

(-4z+40)

We get rid of parentheses

-4z+40

Back to the equation:

-(-4z+40)



We add all the numbers together, and all the variables

-12z-(-4z+40)+57=0

We get rid of parentheses

-12z+4z-40+57=0

We add all the numbers together, and all the variables

-8z+17=0

We move all terms containing z to the left, all other terms to the right

-8z=-17

z=-17/-8

z=2+1/8

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