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(-1/5)p+(9/5)p+6=30
We move all terms to the left:
(-1/5)p+(9/5)p+6-(30)=0
Domain of the equation: 5)p!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
(-1/5)p+(+9/5)p+6-30=0
We add all the numbers together, and all the variables
(-1/5)p+(+9/5)p-24=0
We multiply parentheses
-1p^2+9p^2-24=0
We add all the numbers together, and all the variables
8p^2-24=0
a = 8; b = 0; c = -24;
Δ = b2-4ac
Δ = 02-4·8·(-24)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*8}=\frac{0-16\sqrt{3}}{16} =-\frac{16\sqrt{3}}{16} =-\sqrt{3} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*8}=\frac{0+16\sqrt{3}}{16} =\frac{16\sqrt{3}}{16} =\sqrt{3} $
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