y/10+2(y-3)=40

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Solution for y/10+2(y-3)=40 equation: 



y/10+2(y-3)=40

We move all terms to the left:

y/10+2(y-3)-(40)=0

We multiply parentheses

y/10+2y-6-40=0

We multiply all the terms by the denominator


y+2y*10-6*10-40*10=0

We add all the numbers together, and all the variables

y+2y*10-460=0

Wy multiply elements

y+20y-460=0

We add all the numbers together, and all the variables

21y-460=0

We move all terms containing y to the left, all other terms to the right

21y=460

y=460/21

y=21+19/21

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