(-1/2)x-(1/2)x+4+12=17x-6(3x+(5/6)

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Solution for (-1/2)x-(1/2)x+4+12=17x-6(3x+(5/6) equation: 



(-1/2)x-(1/2)x+4+12=17x-6(3x+(5/6)

We move all terms to the left:

(-1/2)x-(1/2)x+4+12-(17x-6(3x+(5/6))=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(-1/2)x-(+1/2)x-(17x-6(3x+(+5/6))+4+12=0

We multiply parentheses

-1x^2-x^2-(17x-6(3x+(+5/6))+4+12=0

We multiply all the terms by the denominator


-1x^2*6))+4+12-x^2*6))+4+12-(17x-6(3x+(+5=0

Wy multiply elements

-36x^4=0

We do not support expression: x^4

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