(-1/2)x-(-3)=3

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Solution for (-1/2)x-(-3)=3 equation: 



(-1/2)x-(-3)=3

We move all terms to the left:

(-1/2)x-(-3)-(3)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



determiningTheFunctionDomain
(-1/2)x-3-(-3)=0

We add all the numbers together, and all the variables

(-1/2)x=0

We multiply parentheses

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$

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