6(u+4)=4u+28

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Solution for 6(u+4)=4u+28 equation: 



6(u+4)=4u+28

We move all terms to the left:

6(u+4)-(4u+28)=0

We multiply parentheses

6u-(4u+28)+24=0

We get rid of parentheses

6u-4u-28+24=0

We add all the numbers together, and all the variables

2u-4=0

We move all terms containing u to the left, all other terms to the right

2u=4

u=4/2

u=2

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