((x-6)/6)-((2x+8)/2)=12

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Solution for ((x-6)/6)-((2x+8)/2)=12 equation:



((x-6)/6)-((2x+8)/2)=12
We move all terms to the left:
((x-6)/6)-((2x+8)/2)-(12)=0
We calculate fractions
(2x-12)/()+(-12x-48)/()-12=0
We multiply all the terms by the denominator
(2x-12)+(-12x-48)-12*()=0
We add all the numbers together, and all the variables
(2x-12)+(-12x-48)=0
We get rid of parentheses
2x-12x-12-48=0
We add all the numbers together, and all the variables
-10x-60=0
We move all terms containing x to the left, all other terms to the right
-10x=60
x=60/-10
x=-6

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