((x-4)/7)-((3(x-2))/10)=(2x+2)/5

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Solution for ((x-4)/7)-((3(x-2))/10)=(2x+2)/5 equation: 


x in (-oo:+oo)

(x-4)/7-((3*(x-2))/10) = (2*x+2)/5 // - (2*x+2)/5

(x-4)/7-((3*(x-2))/10)-((2*x+2)/5) = 0

(x-4)/7+(-3/10)*(x-2)-((2*x+2)/5) = 0

(x-4)/7-3/10*(x-2)+(-1*(2*x+2))/5 = 0

(5*(x-4))/(5*7)+(-3/10*5*7*(x-2))/(5*7)+(-1*7*(2*x+2))/(5*7) = 0

5*(x-4)-3/10*5*7*(x-2)-1*7*(2*x+2) = 0

1-11/2*x-14*x-14 = 0

-39/2*x-13 = 0

(-39/2*x-13)/(5*7) = 0

(-39/2*x-13)/(5*7) = 0 // * 5*7

-39/2*x-13 = 0

-39/2*x-13 = 0 // + 13

-39/2*x = 13 // : -39/2

x = 13/(-39/2)

x = -2/3

x = -2/3

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