((x-4)/7)-((3(a-2))/10)=(2a+2)/5

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Solution for ((x-4)/7)-((3(a-2))/10)=(2a+2)/5 equation: 


x in (-oo:+oo)

(x-4)/7-((3*(a-2))/10) = (2*a+2)/5 // - (2*a+2)/5

(x-4)/7-((3*(a-2))/10)-((2*a+2)/5) = 0

(x-4)/7+(-3/10)*(a-2)-((2*a+2)/5) = 0

(x-4)/7-3/10*(a-2)+(-1*(2*a+2))/5 = 0

(5*(x-4))/(5*7)+(-3/10*5*7*(a-2))/(5*7)+(-1*7*(2*a+2))/(5*7) = 0

5*(x-4)-3/10*5*7*(a-2)-1*7*(2*a+2) = 0

5*x-21/2*a-14*a-14+1 = 0

5*x-49/2*a-13 = 0

(5*x-49/2*a-13)/(5*7) = 0

(5*x-49/2*a-13)/(5*7) = 0 // * 5*7

5*x-49/2*a-13 = 0

5*x-49/2*a-13 = 0 // + -49/2*a-13

5*x = -(-49/2*a-13) // : 5

x = (-(-49/2*a-13))/5

x = (13-(-49/2*a))/5

x = (13-(-49/2*a))/5

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