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((x-1)/3)+((x+3)/4)=1
We move all terms to the left:
((x-1)/3)+((x+3)/4)-(1)=0
We calculate fractions
(4x-4)/()+(3x+9)/()-1=0
We multiply all the terms by the denominator
(4x-4)+(3x+9)-1*()=0
We add all the numbers together, and all the variables
(4x-4)+(3x+9)=0
We get rid of parentheses
4x+3x-4+9=0
We add all the numbers together, and all the variables
7x+5=0
We move all terms containing x to the left, all other terms to the right
7x=-5
x=-5/7
x=-5/7
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