((x+3)/10)+((x-2)/5)=2

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Solution for ((x+3)/10)+((x-2)/5)=2 equation:



((x+3)/10)+((x-2)/5)=2
We move all terms to the left:
((x+3)/10)+((x-2)/5)-(2)=0
We calculate fractions
(5x+15)/()+(10x-20)/()-2=0
We multiply all the terms by the denominator
(5x+15)+(10x-20)-2*()=0
We add all the numbers together, and all the variables
(5x+15)+(10x-20)=0
We get rid of parentheses
5x+10x+15-20=0
We add all the numbers together, and all the variables
15x-5=0
We move all terms containing x to the left, all other terms to the right
15x=5
x=5/15
x=1/3

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