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(2x-1)/(x+3)=9
We move all terms to the left:
(2x-1)/(x+3)-(9)=0
Domain of the equation: (x+3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(2x-1)-9*(x+3)=0
We multiply parentheses
(2x-1)-9x-27=0
We get rid of parentheses
2x-9x-1-27=0
We add all the numbers together, and all the variables
-7x-28=0
We move all terms containing x to the left, all other terms to the right
-7x=28
x=28/-7
x=-4
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