((x+1)/7)-((x-2)/3))=-4

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Solution for ((x+1)/7)-((x-2)/3))=-4 equation: 



((x+1)/7)-((x-2)/3))=-4

We move all terms to the left:

((x+1)/7)-((x-2)/3))-(-4)=0

We add all the numbers together, and all the variables

((x+1)/7)-((x-2)/3))-(=0

We calculate fractions


(((x+1)*3))+(-7x+14)/()-()/()=0



We calculate terms in parentheses: +(((x+1)*3)), so:

((x+1)*3)



We calculate terms in parentheses: +((x+1)*3), so:

(x+1)*3

We multiply parentheses

3x+3

Back to the equation:

+(3x+3)



We get rid of parentheses

3x+3

Back to the equation:

+(3x+3)



We add all the numbers together, and all the variables

(3x+3)+(-7x+14)/()-1=0

We get rid of parentheses

3x+(-7x+14)/()+3-1=0

We multiply all the terms by the denominator


3x*()+(-7x+14)+3*()-1*()=0

We add all the numbers together, and all the variables

3x*()+(-7x+14)=0

We get rid of parentheses

3x*()-7x+14=0

We add all the numbers together, and all the variables

-7x+3x*()+14=0

We move all terms containing x to the left, all other terms to the right

-7x+3x*()=-14

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