35=(u+5)-7u

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Solution for 35=(u+5)-7u equation:



35=(u+5)-7u
We move all terms to the left:
35-((u+5)-7u)=0
We calculate terms in parentheses: -((u+5)-7u), so:
(u+5)-7u
We add all the numbers together, and all the variables
-7u+(u+5)
We get rid of parentheses
-7u+u+5
We add all the numbers together, and all the variables
-6u+5
Back to the equation:
-(-6u+5)
We get rid of parentheses
6u-5+35=0
We add all the numbers together, and all the variables
6u+30=0
We move all terms containing u to the left, all other terms to the right
6u=-30
u=-30/6
u=-5

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