((x+1)/4)+((x+3)/7)=1

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Solution for ((x+1)/4)+((x+3)/7)=1 equation: 



((x+1)/4)+((x+3)/7)=1

We move all terms to the left:

((x+1)/4)+((x+3)/7)-(1)=0

We calculate fractions


(7x+7)/()+(4x+12)/()-1=0

We multiply all the terms by the denominator


(7x+7)+(4x+12)-1*()=0

We add all the numbers together, and all the variables

(7x+7)+(4x+12)=0

We get rid of parentheses

7x+4x+7+12=0

We add all the numbers together, and all the variables

11x+19=0

We move all terms containing x to the left, all other terms to the right

11x=-19

x=-19/11

x=-1+8/11

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