6(2x-3)=4(2x-3)-11

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Solution for 6(2x-3)=4(2x-3)-11 equation: 



6(2x-3)=4(2x-3)-11

We move all terms to the left:

6(2x-3)-(4(2x-3)-11)=0

We multiply parentheses

12x-(4(2x-3)-11)-18=0



We calculate terms in parentheses: -(4(2x-3)-11), so:

4(2x-3)-11

We multiply parentheses

8x-12-11

We add all the numbers together, and all the variables

8x-23

Back to the equation:

-(8x-23)



We get rid of parentheses

12x-8x+23-18=0

We add all the numbers together, and all the variables

4x+5=0

We move all terms containing x to the left, all other terms to the right

4x=-5

x=-5/4

x=-1+1/4

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