((v-3)/(v+1))+1=((v+7)/(v+4))

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Solution for ((v-3)/(v+1))+1=((v+7)/(v+4)) equation: 


D( v )

v+4 = 0

v+1 = 0

v+4 = 0

v+4 = 0

v+4 = 0 // - 4

v = -4

v+1 = 0

v+1 = 0

v+1 = 0 // - 1

v = -1

v in (-oo:-4) U (-4:-1) U (-1:+oo)

(v-3)/(v+1)+1 = (v+7)/(v+4) // - (v+7)/(v+4)

(v-3)/(v+1)-((v+7)/(v+4))+1 = 0

(v-3)/(v+1)+(-1*(v+7))/(v+4)+1 = 0

((v-3)*(v+4))/((v+1)*(v+4))+(-1*(v+7)*(v+1))/((v+1)*(v+4))+(1*(v+1)*(v+4))/((v+1)*(v+4)) = 0

(v-3)*(v+4)-1*(v+7)*(v+1)+1*(v+1)*(v+4) = 0

v^2-7*v+5*v-19+4 = 0

v^2-2*v-15 = 0

v^2-2*v-15 = 0

v^2-2*v-15 = 0

DELTA = (-2)^2-(-15*1*4)

DELTA = 64

DELTA > 0

v = (64^(1/2)+2)/(1*2) or v = (2-64^(1/2))/(1*2)

v = 5 or v = -3

(v+3)*(v-5) = 0

((v+3)*(v-5))/((v+1)*(v+4)) = 0

((v+3)*(v-5))/((v+1)*(v+4)) = 0 // * (v+1)*(v+4)

(v+3)*(v-5) = 0

( v+3 )

v+3 = 0 // - 3

v = -3

( v-5 )

v-5 = 0 // + 5

v = 5

v in { -3, 5 }

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