(v-3/v+1)+1=(v+7/v+4)

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Solution for (v-3/v+1)+1=(v+7/v+4) equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

v-(3/v)+1+1 = v+7/v+4 // - v+7/v+4

v-v-(3/v)-(7/v)-4+1+1 = 0

v-v-3*v^-1-7*v^-1-4+1+1 = 0

-10*v^-1 = 2 // : -10

v^-1 = -1/5

-1 < 0

1/(v^1) = -1/5 // * v^1

1 = -1/5*v^1 // : -1/5

-5 = v^1

v = -5

v = -5

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