((X+6)/4)+((x+2)/7)=2

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Solution for ((X+6)/4)+((x+2)/7)=2 equation: 



((X+6)/4)+((X+2)/7)=2

We move all terms to the left:

((X+6)/4)+((X+2)/7)-(2)=0

We calculate fractions


(7X+42)/()+(4X+8)/()-2=0

We multiply all the terms by the denominator


(7X+42)+(4X+8)-2*()=0

We add all the numbers together, and all the variables

(7X+42)+(4X+8)=0

We get rid of parentheses

7X+4X+42+8=0

We add all the numbers together, and all the variables

11X+50=0

We move all terms containing X to the left, all other terms to the right

11X=-50

X=-50/11

X=-4+6/11

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