((3x+26)/4)+((x+33)/7)=13

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Solution for ((3x+26)/4)+((x+33)/7)=13 equation: 



((3x+26)/4)+((x+33)/7)=13

We move all terms to the left:

((3x+26)/4)+((x+33)/7)-(13)=0

We calculate fractions


(21x+182)/()+(4x+132)/()-13=0

We multiply all the terms by the denominator


(21x+182)+(4x+132)-13*()=0

We add all the numbers together, and all the variables

(21x+182)+(4x+132)=0

We get rid of parentheses

21x+4x+182+132=0

We add all the numbers together, and all the variables

25x+314=0

We move all terms containing x to the left, all other terms to the right

25x=-314

x=-314/25

x=-12+14/25

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