((6y-48)/5)=-4y

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Solution for ((6y-48)/5)=-4y equation: 



((6y-48)/5)=-4y

We move all terms to the left:

((6y-48)/5)-(-4y)=0

We get rid of parentheses

((6y-48)/5)+4y=0

We multiply all the terms by the denominator


((6y-48)+4y*5)=0



We calculate terms in parentheses: +((6y-48)+4y*5), so:

(6y-48)+4y*5

Wy multiply elements

(6y-48)+20y

We get rid of parentheses

6y+20y-48

We add all the numbers together, and all the variables

26y-48

Back to the equation:

+(26y-48)



We get rid of parentheses

26y-48=0

We move all terms containing y to the left, all other terms to the right

26y=48

y=48/26

y=1+11/13

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