(3x-15)=(x+33)

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Solution for (3x-15)=(x+33) equation: 



(3x-15)=(x+33)

We move all terms to the left:

(3x-15)-((x+33))=0

We get rid of parentheses

3x-((x+33))-15=0



We calculate terms in parentheses: -((x+33)), so:

(x+33)

We get rid of parentheses

x+33

Back to the equation:

-(x+33)



We get rid of parentheses

3x-x-33-15=0

We add all the numbers together, and all the variables

2x-48=0

We move all terms containing x to the left, all other terms to the right

2x=48

x=48/2

x=24

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