((5y-35)/77)/((y-7)/14)

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Solution for ((5y-35)/77)/((y-7)/14) equation: 


D( y )

(y-7)/14 = 0

(y-7)/14 = 0

(y-7)/14 = 0

y-7 = 0 // + 7

y = 7

y in (-oo:7) U (7:+oo)

((5*y-35)/77)/((y-7)/14) = 0

(14*(5*y-35))/(77*(y-7)) = 0

( 14 )

14 = 0

y belongs to the empty set

( 5*y-35 )

5*y-35 = 0 // + 35

5*y = 35 // : 5

y = 35/5

y = 7

y in { 7} 

y belongs to the empty set

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