((5x-8)/4)-((2x+3)/3)+5/4=0

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Solution for ((5x-8)/4)-((2x+3)/3)+5/4=0 equation: 



((5x-8)/4)-((2x+3)/3)+5/4=0

We calculate fractions


(15x-24)/()+(-((2x+3)*4)*4)/()+()/()=0



We calculate terms in parentheses: +(-((2x+3)*4)*4)/(), so:

-((2x+3)*4)*4)/(

We multiply all the terms by the denominator


-((2x+3)*4)*4)



We calculate terms in parentheses: -((2x+3)*4)*4), so:

(2x+3)*4)*4

We multiply parentheses

8x+

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



Back to the equation:

+(-8x)



We add all the numbers together, and all the variables

(15x-24)/()+(-8x)+1=0

We get rid of parentheses

(15x-24)/()-8x+1=0

We multiply all the terms by the denominator


(15x-24)-8x*()+1*()=0

We add all the numbers together, and all the variables

(15x-24)-8x*()=0

We get rid of parentheses

15x-8x*()-24=0

We move all terms containing x to the left, all other terms to the right

15x-8x*()=24

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