(2t-5)(9t+7)=(6t-7)(3t+6)

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Solution for (2t-5)(9t+7)=(6t-7)(3t+6) equation: 



(2t-5)(9t+7)=(6t-7)(3t+6)

We move all terms to the left:

(2t-5)(9t+7)-((6t-7)(3t+6))=0

We multiply parentheses ..

(+18t^2+14t-45t-35)-((6t-7)(3t+6))=0



We calculate terms in parentheses: -((6t-7)(3t+6)), so:

(6t-7)(3t+6)

We multiply parentheses ..

(+18t^2+36t-21t-42)

We get rid of parentheses

18t^2+36t-21t-42

We add all the numbers together, and all the variables

18t^2+15t-42

Back to the equation:

-(18t^2+15t-42)



We get rid of parentheses

18t^2-18t^2+14t-45t-15t-35+42=0

We add all the numbers together, and all the variables

-46t+7=0

We move all terms containing t to the left, all other terms to the right

-46t=-7

t=-7/-46

t=7/46

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