((5x+2)/3)-x=((2x+1)/-2)

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Solution for ((5x+2)/3)-x=((2x+1)/-2) equation: 


x in (-oo:+oo)

(5*x+2)/3-x = (2*x+1)/(-2) // - (2*x+1)/(-2)

(5*x+2)/3-((2*x+1)/(-2))-x = 0

(5*x+2)/3+(-1*(2*x+1))/(-2)-x = 0

(-2*(5*x+2))/(-2*3)+(-1*3*(2*x+1))/(-2*3)+(-2*3*(-x))/(-2*3) = 0

-2*(5*x+2)-1*3*(2*x+1)-2*3*(-x) = 0

6*x-16*x-7 = 0

-10*x-7 = 0

(-10*x-7)/(-2*3) = 0

(-10*x-7)/(-2*3) = 0 // * -2*3

-10*x-7 = 0

-10*x-7 = 0 // + 7

-10*x = 7 // : -10

x = 7/(-10)

x = -7/10

x = -7/10

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