((5x+2)/2)-x=((2x+1)/-2)

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Solution for ((5x+2)/2)-x=((2x+1)/-2) equation:


x in (-oo:+oo)

(5*x+2)/2-x = (2*x+1)/(-2) // - (2*x+1)/(-2)

(5*x+2)/2-((2*x+1)/(-2))-x = 0

(5*x+2)/2+(-1*(2*x+1))/(-2)-x = 0

(-2*(5*x+2))/(-2*2)+(-1*2*(2*x+1))/(-2*2)+(-2*2*(-x))/(-2*2) = 0

-2*(5*x+2)-1*2*(2*x+1)-2*2*(-x) = 0

4*x-14*x-6 = 0

-10*x-6 = 0

(-10*x-6)/(-2*2) = 0

(-10*x-6)/(-2*2) = 0 // * -2*2

-10*x-6 = 0

-10*x-6 = 0 // + 6

-10*x = 6 // : -10

x = 6/(-10)

x = -3/5

x = -3/5

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