((4x-2)/5)+2=2+x

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Solution for ((4x-2)/5)+2=2+x equation: 



((4x-2)/5)+2=2+x

We move all terms to the left:

((4x-2)/5)+2-(2+x)=0

We add all the numbers together, and all the variables

((4x-2)/5)-(x+2)+2=0

We get rid of parentheses

((4x-2)/5)-x-2+2=0

We multiply all the terms by the denominator


((4x-2)-x*5)-2*5)+2*5)=0



We calculate terms in parentheses: +((4x-2)-x*5), so:

(4x-2)-x*5

Wy multiply elements

(4x-2)-5x

We get rid of parentheses

4x-5x-2

We add all the numbers together, and all the variables

-1x-2

Back to the equation:

+(-1x-2)



We add all the numbers together, and all the variables

(-1x-2)=0

We get rid of parentheses

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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