68=(20x+50)=2

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Solution for 68=(20x+50)=2 equation:



68=(20x+50)=2
We move all terms to the left:
68-((20x+50))=0
We calculate terms in parentheses: -((20x+50)), so:
(20x+50)
We get rid of parentheses
20x+50
Back to the equation:
-(20x+50)
We get rid of parentheses
-20x-50+68=0
We add all the numbers together, and all the variables
-20x+18=0
We move all terms containing x to the left, all other terms to the right
-20x=-18
x=-18/-20
x=9/10

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