((4/5)(x))-x=-12

Solution for ((4/5)(x))-x=-12 equation:

((4/5)(x))-x=-12

We move all terms to the left:

((4/5)(x))-x-(-12)=0


Domain of the equation: 5)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

((+4/5)x)-x-(-12)=0

We add all the numbers together, and all the variables

-1x+((+4/5)x)+12=0

We multiply all the terms by the denominator


-1x*5)x)+((+12*5)x)+4=0

We add all the numbers together, and all the variables

-1x*5)x)+(60x)+4=0

We add all the numbers together, and all the variables

-1x*5)x)+60x+4=0

Wy multiply elements

-5x^2=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-10}=0$