2+(4h-1)=5+2(1+2h)

Solution for 2+(4h-1)=5+2(1+2h) equation:

2+(4h-1)=5+2(1+2h)

We move all terms to the left:

2+(4h-1)-(5+2(1+2h))=0

We add all the numbers together, and all the variables

(4h-1)-(5+2(2h+1))+2=0

We get rid of parentheses

4h-(5+2(2h+1))-1+2=0


We calculate terms in parentheses: -(5+2(2h+1)), so:

5+2(2h+1)

determiningTheFunctionDomain
2(2h+1)+5

We multiply parentheses

4h+2+5

We add all the numbers together, and all the variables

4h+7

Back to the equation:

-(4h+7)


We add all the numbers together, and all the variables

4h-(4h+7)+1=0

We get rid of parentheses

4h-4h-7+1=0

We add all the numbers together, and all the variables

-6!=0

There is no solution for this equation