((3x+10)/5)+(3/4)=((-7x)/5)

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Solution for ((3x+10)/5)+(3/4)=((-7x)/5) equation: 



((3x+10)/5)+(3/4)=((-7x)/5)

We move all terms to the left:

((3x+10)/5)+(3/4)-(((-7x)/5))=0

We add all the numbers together, and all the variables

((3x+10)/5)-(((-7x)/5))+(+3/4)=0

We get rid of parentheses

((3x+10)/5)-(((-7x)/5))+3/4=0

We calculate fractions


(((3x+10)*5))*4)/()+(-(((-7x)*5)*4)/()+()/()=0



We calculate terms in parentheses: -(((-7x)*5)*4)/(), so:

((-7x)*5)*4)/(

We multiply all the terms by the denominator


((-7x)*5)*4)



We calculate terms in parentheses: +((-7x)*5)*4), so:

(-7x)*5)*4

We multiply parentheses

-140x

Back to the equation:

+(-140x)



We get rid of parentheses

-140x

Back to the equation:

-(-140x)



We add all the numbers together, and all the variables

(((3x+10)*5))*4)/()+(-(-140x)+1=0

We get rid of parentheses

(((3x+10)*5))*4)/()+(+140x+1=0

We multiply all the terms by the denominator


(((3x+10)*5))*4)+140x*()+(+1*()+(=0

We add all the numbers together, and all the variables

(((3x+10)*5))*4)+140x*()+(=0

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