9n+7+n+3=9(1+n)+11(n-9)

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Solution for 9n+7+n+3=9(1+n)+11(n-9) equation: 



9n+7+n+3=9(1+n)+11(n-9)

We move all terms to the left:

9n+7+n+3-(9(1+n)+11(n-9))=0

We add all the numbers together, and all the variables

9n+n-(9(n+1)+11(n-9))+7+3=0

We add all the numbers together, and all the variables

10n-(9(n+1)+11(n-9))+10=0



We calculate terms in parentheses: -(9(n+1)+11(n-9)), so:

9(n+1)+11(n-9)

We multiply parentheses

9n+11n+9-99

We add all the numbers together, and all the variables

20n-90

Back to the equation:

-(20n-90)



We get rid of parentheses

10n-20n+90+10=0

We add all the numbers together, and all the variables

-10n+100=0

We move all terms containing n to the left, all other terms to the right

-10n=-100

n=-100/-10

n=+10

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