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((3x)/4)+2=(4x)-1
We move all terms to the left:
((3x)/4)+2-((4x)-1)=0
We add all the numbers together, and all the variables
(+3x/4)-(4x-1)+2=0
We get rid of parentheses
3x/4-4x+1+2=0
We multiply all the terms by the denominator
3x-4x*4+1*4+2*4=0
We add all the numbers together, and all the variables
3x-4x*4+12=0
Wy multiply elements
3x-16x+12=0
We add all the numbers together, and all the variables
-13x+12=0
We move all terms containing x to the left, all other terms to the right
-13x=-12
x=-12/-13
x=12/13
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