8(x+-2)=27(x+-2)+10

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Solution for 8(x+-2)=27(x+-2)+10 equation: 



8(x+-2)=27(x+-2)+10

We move all terms to the left:

8(x+-2)-(27(x+-2)+10)=0

We add all the numbers together, and all the variables

8(x-2)-(27(x-2)+10)=0

We multiply parentheses

8x-(27(x-2)+10)-16=0



We calculate terms in parentheses: -(27(x-2)+10), so:

27(x-2)+10

We multiply parentheses

27x-54+10

We add all the numbers together, and all the variables

27x-44

Back to the equation:

-(27x-44)



We get rid of parentheses

8x-27x+44-16=0

We add all the numbers together, and all the variables

-19x+28=0

We move all terms containing x to the left, all other terms to the right

-19x=-28

x=-28/-19

x=1+9/19

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