((2y-9)/10)+(3/2)=y

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Solution for ((2y-9)/10)+(3/2)=y equation: 



((2y-9)/10)+(3/2)=y

We move all terms to the left:

((2y-9)/10)+(3/2)-(y)=0

We add all the numbers together, and all the variables

((2y-9)/10)-y+(+3/2)=0

We add all the numbers together, and all the variables

-1y+((2y-9)/10)+(+3/2)=0

We get rid of parentheses

-1y+((2y-9)/10)+3/2=0

We calculate fractions


-1y+(((2y-9)*2)/()+()/()=0



We calculate terms in parentheses: +(((2y-9)*2)/()+()/(), so:

((2y-9)*2)/()+()/(

We add all the numbers together, and all the variables

((2y-9)*2)/()+1

We multiply all the terms by the denominator


((2y-9)*2)+1*()



We calculate terms in parentheses: +((2y-9)*2), so:

(2y-9)*2

We multiply parentheses

4y-18

Back to the equation:

+(4y-18)



We add all the numbers together, and all the variables

(4y-18)

We get rid of parentheses

4y-18

Back to the equation:

+(4y-18)



We get rid of parentheses

-1y+4y-18=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6

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