b1+(b1+2)=8

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Solution for b1+(b1+2)=8 equation: 



b1+(b1+2)=8

We move all terms to the left:

b1+(b1+2)-(8)=0

We add all the numbers together, and all the variables

b1+(b+2)-8=0

We add all the numbers together, and all the variables

b+(b+2)-8=0

We get rid of parentheses

b+b+2-8=0

We add all the numbers together, and all the variables

2b-6=0

We move all terms containing b to the left, all other terms to the right

2b=6

b=6/2

b=3

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