((2x-5)/7)=4

Solution for ((2x-5)/7)=4 equation:

((2x-5)/7)=4

We move all terms to the left:

((2x-5)/7)-(4)=0

We multiply all the terms by the denominator


((2x-5)-4*7)=0


We calculate terms in parentheses: +((2x-5)-4*7), so:

(2x-5)-4*7

We add all the numbers together, and all the variables

(2x-5)-28

We get rid of parentheses

2x-5-28

We add all the numbers together, and all the variables

2x-33

Back to the equation:

+(2x-33)


We get rid of parentheses

2x-33=0

We move all terms containing x to the left, all other terms to the right

2x=33

x=33/2

x=16+1/2