1/4(m-12)=-3/4m+3

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Solution for 1/4(m-12)=-3/4m+3 equation: 



1/4(m-12)=-3/4m+3

We move all terms to the left:

1/4(m-12)-(-3/4m+3)=0



Domain of the equation: 4(m-12)!=0

m∈R





Domain of the equation: 4m+3)!=0

m∈R



We get rid of parentheses

1/4(m-12)+3/4m-3=0

We calculate fractions


4m/(16m^2-192m)+(12mm/(16m^2-192m)-3=0

We calculate fractions

We do not support empression: m^3

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