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((2x+8)/5)=3x-1
We move all terms to the left:
((2x+8)/5)-(3x-1)=0
We get rid of parentheses
((2x+8)/5)-3x+1=0
We multiply all the terms by the denominator
((2x+8)-3x*5)+1*5)=0
We calculate terms in parentheses: +((2x+8)-3x*5), so:We add all the numbers together, and all the variables
(2x+8)-3x*5
Wy multiply elements
(2x+8)-15x
We get rid of parentheses
2x-15x+8
We add all the numbers together, and all the variables
-13x+8
Back to the equation:
+(-13x+8)
(-13x+8)=0
We get rid of parentheses
-13x+8=0
We move all terms containing x to the left, all other terms to the right
-13x=-8
x=-8/-13
x=8/13
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