3z(-2z+2)=60

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Solution for 3z(-2z+2)=60 equation: 



3z(-2z+2)=60

We move all terms to the left:

3z(-2z+2)-(60)=0

We multiply parentheses

-6z^2+6z-60=0

a = -6; b = 6; c = -60;
Δ = b2-4ac
Δ = 62-4·(-6)·(-60)
Δ = -1404
Delta is less than zero, so there is no solution for the equation

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