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((2x+3)/4)-((3x-5)/3)=2
We move all terms to the left:
((2x+3)/4)-((3x-5)/3)-(2)=0
We calculate fractions
(6x+9)/()+(-12x+20)/()-2=0
We multiply all the terms by the denominator
(6x+9)+(-12x+20)-2*()=0
We add all the numbers together, and all the variables
(6x+9)+(-12x+20)=0
We get rid of parentheses
6x-12x+9+20=0
We add all the numbers together, and all the variables
-6x+29=0
We move all terms containing x to the left, all other terms to the right
-6x=-29
x=-29/-6
x=4+5/6
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