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5-2x(2x+1)=-6
We move all terms to the left:
5-2x(2x+1)-(-6)=0
We add all the numbers together, and all the variables
-2x(2x+1)+11=0
We multiply parentheses
-4x^2-2x+11=0
a = -4; b = -2; c = +11;
Δ = b2-4ac
Δ = -22-4·(-4)·11
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6\sqrt{5}}{2*-4}=\frac{2-6\sqrt{5}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6\sqrt{5}}{2*-4}=\frac{2+6\sqrt{5}}{-8} $
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