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((2x+20)/(2x)=5x-4
We move all terms to the left:
((2x+20)/(2x)-(5x-4)=0
Domain of the equation: 2x-(5x-4)!=0We multiply all the terms by the denominator
x∈R
((2x+20)=0
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| -6X+7y=19 | | 11^(3x)=5^(-4-7) | | 7b/8=14 | | 4m+2.8=27 | | 9x=32.4 | | 76=-4x=40 | | y4-5y2+4=0 | | 18+8x=21 | | 12x^2=10-7x | | 6x+10)+(x+2)+x=180 | | 7w-60=6 | | x-2.63=1.87 | | 2k/5=10 | | 3=v/2-8 | | w/5+15=26 | | 3*(y+2)+0.5y=41 | | 76=24e | | 68=35f | | 45=11x-6x | | 2*(a+4)+0.5a=23 | | -4=-2+a/8 | | (x-2)-9=4-(x+2) | | 4x6=3x2x5 | | x-70=14(x-500-189 | | x-70=14(x-50)-189 | | 8x+48=-2(2x-36) | | 5/7x-19=6 | | 0.5(8x-20)=3(x+12) | | 4(x-200)=0.5x-100 | | 2^x=15.8 | | 1=3(j-8)+-5 | | 4.9t^2+34.3t+294=0 |