((2x+1)/4)-((x-4)/6)=1

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Solution for ((2x+1)/4)-((x-4)/6)=1 equation: 



((2x+1)/4)-((x-4)/6)=1

We move all terms to the left:

((2x+1)/4)-((x-4)/6)-(1)=0

We calculate fractions


(12x+6)/()+(-4x+16)/()-1=0

We multiply all the terms by the denominator


(12x+6)+(-4x+16)-1*()=0

We add all the numbers together, and all the variables

(12x+6)+(-4x+16)=0

We get rid of parentheses

12x-4x+6+16=0

We add all the numbers together, and all the variables

8x+22=0

We move all terms containing x to the left, all other terms to the right

8x=-22

x=-22/8

x=-2+3/4

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