(2p+9)(3p+1)=0

Solution for (2p+9)(3p+1)=0 equation:

(2p+9)(3p+1)=0

We multiply parentheses ..

(+6p^2+2p+27p+9)=0

We get rid of parentheses

6p^2+2p+27p+9=0

We add all the numbers together, and all the variables

6p^2+29p+9=0

a = 6; b = 29; c = +9;
Δ = b2-4ac
Δ = 292-4·6·9
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-25}{2*6}=\frac{-54}{12}
=-4+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+25}{2*6}=\frac{-4}{12}
=-1/3
$