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((24+2x)/x)-1=(2x+3)/3
We move all terms to the left:
((24+2x)/x)-1-((2x+3)/3)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((2x+24)/x)-((2x+3)/3)-1=0
We calculate fractions
(6x+72)/x*3))+(-2x^2-3x)/x*3))-1=0
We can not solve this equation
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