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5y+3y(2+y)=54
We move all terms to the left:
5y+3y(2+y)-(54)=0
We add all the numbers together, and all the variables
5y+3y(y+2)-54=0
We multiply parentheses
3y^2+5y+6y-54=0
We add all the numbers together, and all the variables
3y^2+11y-54=0
a = 3; b = 11; c = -54;
Δ = b2-4ac
Δ = 112-4·3·(-54)
Δ = 769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{769}}{2*3}=\frac{-11-\sqrt{769}}{6} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{769}}{2*3}=\frac{-11+\sqrt{769}}{6} $
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